Wednesday, May 16, 2012
1) Direct System
It is used for the measurement of weight per unit length of yarn.
When count increases, fineness decreases. ( count↑ fineness↓ )
Commonly used units in this system of measurement are:-
1) Tex ( 1 Tex = 1g/ 1000m )
2) Grex ( 1 Grex = 1g/ 10,000m )
3) Denier ( 1 Denier = 1g/ 9000m )
2) Indirect System
It is used for the measurement of length per unit weight of yarn.
When count increases, fineness increases. ( count↑ fineness↑ )
Commonly used subsystems of indirect system are:-
1) English System ( 1 Ne = 1 Hank/ lb )
2) Metric System ( 1 Nm = 1 Km/ kg )
1) English System ( 1 Ne = 1 Hank/ lb )
2) Metric System ( 1 Nm = 1 Km/ kg )
For cotton yarn, length of 1 Hank = 840 yards. Whenever the type of count is not mentioned with the count, it is understood that it is the English count.
Count Conversion Table
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1) Calculate the length of a package of 80/1 and cone weight 2.083 lb.
(Note:- English count is represented as C/N i-e, yarn count/ no. of yarn plies)
Yarn type = 80/1
Cone wt. = 2.083 lb
Cone length = ?
Yarn type = 80/1
Cone wt. = 2.083 lb
Cone length = ?
Solution:
Length= Ne x lb x 840 yards
= 80 x 2.083 x 840 yards
= (139977.6÷ 1.0936 )m
= 127997.07 m ------------Ans.
2) Calculate the length of yarn with Ne (80/2) and weight 4.166 lb.
Yarn type = 80/2
Cone weight = 4.166 lb
Cone length = ?
Solution:
Length = Ne x lb x 840 yards
= (80÷2)x 4.166 x 840 yards
= (139977.6÷1.0936)m
= 127997.07 m ---------------Ans.
3) Calculate the draft at drawing frame if the feeding sliver is 68 grains/yard, delivered sliver is 48 grains/ yard and the number of doublings is 8 :-
Count of feeding sliver = 68 gr/ yd
Count of delivered sliver = 48 gr/ yd
Doubling = 8 (8 sliver cans used)
Draft = ?
Count of delivered sliver = 48 gr/ yd
Doubling = 8 (8 sliver cans used)
Draft = ?
Solution:
Actual draft = (count fed x doubling) ÷ (count delivered) (direct system)
= (68 x 8)÷ 48
= 11.33-------------Ans.
4) Calculate the grains/ yard of delivered sliver if feeding sliver is 68, doubling is 6 and the draft is 7 :-
Count of F.S = 68
Count of D.S = ?
Doubling = 6
Draft = 7
Count of F.S = 68
Count of D.S = ?
Doubling = 6
Draft = 7
Solution :
A.D = (F.S x D)÷ D.S
=> 7 = (68 x 6)÷D.S
=>D.S = 68 x 6 = 58.28 grains/ yard ----------Ans.
5) Calculate the TPI on simplex if the diameter of back roller is 15/16”, rpm of B.R is 10, rpm of flyer is 1000 and draft is 6 :
TPI on simplex = ?
Dia. of B.R = 15/16”
Dia. of F.R = ?
Rpm of B.R = 10
Rpm of flyer = 1000 rpm
Draft, D = 6
TPI on simplex = ?
Dia. of B.R = 15/16”
Dia. of F.R = ?
Rpm of B.R = 10
Rpm of flyer = 1000 rpm
Draft, D = 6
Solution :
S.S of B.R = πDN = π x 15/16” x 10 = 29.45”/ min
D = (S.S of F.R) ÷ (S.S of B.R)
=> 6 = (S.S of F.R)÷29.45
=> S.S of F.R = 6 x 29.45 = 176.71”/ min
TPI = rpm of flyer ÷ S.S of F.R = 1000 ÷ 176.71 = 5.66 -----------------Ans.
Solution :
Dia. of Front roller = 2.8 cm / 2.54 (1 in= 2.54 cm)
Surface speed of F.R, ^DN = π x dia. of F.R x rpm of F.R
= π x 1.1023 x 30
= 103.88 “/ min.
6) Calculate the TPI (twists per inch) produced on a simplex with diameter of front roller 28 mm and its rpm be 30. The rpm of flyer is 1000.
TPI on simplex = ?
Dia. of F.R = 28 mm = 2.8 cm
Rpm of F.R = 30
Rpm of flyer = 1000
TPI on simplex = ?
Dia. of F.R = 28 mm = 2.8 cm
Rpm of F.R = 30
Rpm of flyer = 1000
Solution :
Dia. of Front roller = 2.8 cm / 2.54 (1 in= 2.54 cm)
= 1.1023 inch
Surface speed of F.R, ^DN = π x dia. of F.R x rpm of F.R
= π x 1.1023 x 30
= 103.88 “/ min.
TPI = rpm of flyer ÷ S.S of F.R = 1000 ÷ 103.88
= 9.63 -----------------Ans.
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